Alphabet Rangoli in Python - HackerRank Solution

Problem Statement :

You are given an integer, N. Your task is to print an alphabet rangoli of size N. (Rangoli is a form of Indian folk art based on creation of patterns.)

Different sizes of alphabet rangoli are shown below:

#size 3

----c----

--c-b-c--

c-b-a-b-c

--c-b-c--

----c----

#size 5

--------e--------

------e-d-e------

----e-d-c-d-e----

--e-d-c-b-c-d-e--

e-d-c-b-a-b-c-d-e

--e-d-c-b-c-d-e--

----e-d-c-d-e----

------e-d-e------

--------e--------

#size 10

------------------j------------------

----------------j-i-j----------------

--------------j-i-h-i-j--------------

------------j-i-h-g-h-i-j------------

----------j-i-h-g-f-g-h-i-j----------

--------j-i-h-g-f-e-f-g-h-i-j--------

------j-i-h-g-f-e-d-e-f-g-h-i-j------

----j-i-h-g-f-e-d-c-d-e-f-g-h-i-j----

--j-i-h-g-f-e-d-c-b-c-d-e-f-g-h-i-j--

j-i-h-g-f-e-d-c-b-a-b-c-d-e-f-g-h-i-j

--j-i-h-g-f-e-d-c-b-c-d-e-f-g-h-i-j--

----j-i-h-g-f-e-d-c-d-e-f-g-h-i-j----

------j-i-h-g-f-e-d-e-f-g-h-i-j------

--------j-i-h-g-f-e-f-g-h-i-j--------

----------j-i-h-g-f-g-h-i-j----------

------------j-i-h-g-h-i-j------------

--------------j-i-h-i-j--------------

----------------j-i-j----------------

------------------j------------------

The center of the rangoli has the first alphabet letter a, and the boundary has the Nth alphabet letter (in alphabetical order).

Input Format:

Only one line of input containing N, the size of the rangoli.

Constraints:

0<N<27

Output Format:

Print the alphabet rangoli in the format explained above.

Solution:

n=int(input())
for i in range(n-1,-1,-1):
    for j in range(i):
        print(end="--")
    for j in range(n-1,i,-1):
        print(chr(j+97),end="-")
    for j in range(i,n):
        if j != n-1:
            print(chr(j+97),end="-")
        else:
            print(chr(j+97),end="")
    for j in range(2*i):
        print(end="-")
    print()
for i in range(1,n):
    for j in range(i):
        print(end="--")
    for j in range(n-1,i,-1):
        print(chr(j+97),end="-")
    for j in range(i,n):
        if j != n-1:
            print(chr(j+97),end="-")
        else:
            print(chr(j+97),end="")
    for j in range(2*i):
        print(end="-")
    print()