Designer Door Mat in Python - HackerRank Solution

Problem Statement :

Mr. Vincent works in a door mat manufacturing company. One day, he designed a new door mat with the following specifications:

     1. Mat size must be MXN. (N is an odd natural number, and M is 3 times N.)

     2. The design should have 'WELCOME' written in the center. 

     3. The design pattern should only use |, . and - characters.

Sample Designs:

    Size: 7 x 21 
    ---------.|.---------
    ------.|..|..|.------
    ---.|..|..|..|..|.---
    -------WELCOME-------
    ---.|..|..|..|..|.---
    ------.|..|..|.------
    ---------.|.---------
    
    Size: 11 x 33
    ---------------.|.---------------
    ------------.|..|..|.------------
    ---------.|..|..|..|..|.---------
    ------.|..|..|..|..|..|..|.------
    ---.|..|..|..|..|..|..|..|..|.---
    -------------WELCOME-------------
    ---.|..|..|..|..|..|..|..|..|.---
    ------.|..|..|..|..|..|..|.------
    ---------.|..|..|..|..|.---------
    ------------.|..|..|.------------
    ---------------.|.---------------

Input Format:

A single line containing the space separated values of M and N.

Constraints:

3<N<101

15<M<303

Output Format:

Output the design pattern.

Solution:

n,m=input().split()
c='|'
v='.'

n=int(n)
m=int(m)
j=n//2-1
for i in range(n):
    if i==n//2:
        print('WELCOME'.center(m,'-'))
    else:
        if i<n/2:    
            print(((v+c+v)*(2*i+1)).center(m,'-'))
        else:
            print(((v+c+v)*(2*j+1)).center(m,'-'))
            j=j-1