String Validators in Python - HackerRank Solution
Problem Statement :
Python has built-in string validation methods for basic data. It can check if a string is composed of alphabetical characters, alphanumeric characters, digits, etc.
str.isalnum()
This method checks if all the characters of a string are alphanumeric (a-z, A-Z and 0-9).
>>> print 'ab123'.isalnum()
True
>>> print 'ab123#'.isalnum()
False
str.isalpha()
This method checks if all the characters of a string are alphabetical (a-z and A-Z).
>>> print 'abcD'.isalpha()
True
>>> print 'abcd1'.isalpha()
False
str.isdigit()
This method checks if all the characters of a string are digits (0-9).
>>> print '1234'.isdigit()
True
>>> print '123edsd'.isdigit()
False
str.islower()
This method checks if all the characters of a string are lowercase characters (a-z).
>>> print 'abcd123#'.islower()
True
>>> print 'Abcd123#'.islower()
False
str.isupper()
This method checks if all the characters of a string are uppercase characters (A-Z).
>>> print 'ABCD123#'.isupper()
True
>>> print 'Abcd123#'.isupper()
False
Task:
You are given a string S.
Your task is to find out if the string S contains: alphanumeric characters, alphabetical characters, digits, lowercase and uppercase characters.
Input Format:
A single line containing a string S.
Constraints:
0<len(S)<1000
Output Format:
In the first line, print True if S has any alphanumeric characters. Otherwise, print False.
In the second line, print True if S has any alphabetical characters. Otherwise, print False.
In the third line, print True if S has any digits. Otherwise, print False.
In the fourth line, print True if S has any lowercase characters. Otherwise, print False.
In the fifth line, print True if S has any uppercase characters. Otherwise, print False.
Solution:
def pr(t):
if t==1:
print(True)
else:
print(False)
if __name__ == '__main__':
s = input()
t=0
for i in s:
if i.isalnum()==True:
t=1
break
pr(t)
t=0
for i in s:
if i.isalpha()==True:
t=1
break
pr(t)
t=0
for i in s:
if i.isdigit()==True:
t=1
break
pr(t)
t=0
for i in s:
if i.islower()==True:
t=1
break
pr(t)
t=0
for i in s:
if i.isupper()==True:
t=1
break
pr(t)