Text Allignment in Python - HackerRank Solution

Problem Statement :

In Python, a string of text can be aligned left, right and center.

.ljust(width)

This method returns a left aligned string of length width.

>>> width = 20

>>> print 'HackerRank'.ljust(width,'-')

HackerRank---------- 

.center(width)

This method returns a centered string of length width.

>>> width = 20

>>> print 'HackerRank'.center(width,'-')

-----HackerRank-----

.rjust(width)

This method returns a right aligned string of length width.

>>> width = 20

>>> print 'HackerRank'.rjust(width,'-')

----------HackerRank

Task:

You are given a partial code that is used for generating the HackerRank Logo of variable thickness.

Your task is to replace the blank (______) with rjust, ljust or center.

Input Format:

A single line containing the thickness value for the logo.

Constraints:

0<thickness<50

The thickness must be an odd number.

Output Format:

Output the desired logo.

Solution:

#Replace all ______ with rjust, ljust or center. 

thickness = int(input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
    print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
    print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
    print((c*thickness*5).center(thickness*6))    

#Bottom Pillars
for i in range(thickness+1):
    print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))    

#Bottom Cone
for i in range(thickness):
    print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))